Use a while-loop to find the smallest
positive integer $n$, such that $\sqrt{n}-\sqrt{n-1}<0.01$.

Remember that $\sqrt{something}$ in Lua is

What is your answer? a) 2499 b) 2500 c) 2501 or d) 10,000 e) there is no such integer. (From Artino, 1978, #18.)

Remember that $\sqrt{something}$ in Lua is

`math.sqrt(something)`

.
What is your answer? a) 2499 b) 2500 c) 2501 or d) 10,000 e) there is no such integer. (From Artino, 1978, #18.)

`d`

becomes less than 0.01, and fix
the `d=`

line to compute $\sqrt{n}-\sqrt{n-1}<0.01$.
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